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Worked Solutions

Physics — Worked Solutions (Year 10 Science)

By Lucas · Intuition tutor 1 min read

Created with Intu AI

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Worked examples for Year 10 Science physics. Each shows where the marks are awarded, the key idea, and the full solution explained by your choice of tutor — Stella, Ella or Cassie.

How to use these

Try each question first, then check your working. Use the tutor tabs to read the full solution in the style that suits you: Stella is direct and challenging, Ella is warm and explains the why, and Cassie is concise and analytical.

Watch your units and always show the formula before substituting numbers.

Example 1 — Acceleration of a cyclist

Standard 3 marks

Question

A cyclist starts from rest and reaches a speed of $12\ \text{m/s}$ in $6\ \text{s}$ along a straight path. Calculate the cyclist's acceleration, and state what the answer means.

Solution

Acceleration is the change in speed divided by the time taken: $a = \dfrac{v - u}{t}$.

Starting from rest means $u = 0$, with $v = 12\ \text{m/s}$ and $t = 6\ \text{s}$.

$a = \dfrac{12 - 0}{6} = 2\ \text{m/s}^2$.

That means the speed increases by $2\ \text{m/s}$ every second. Always quote the units — $\text{m/s}^2$ is what marks acceleration apart from speed.

Where the marks go

  • 1 mark: Correct formula $a = \dfrac{v - u}{t}$ with $u = 0$ identified
  • 1 mark: Correct value $a = 2\ \text{m/s}^2$ with units
  • 1 mark: States the meaning (speed increases by $2\ \text{m/s}$ each second)

Key idea

Acceleration is the rate of change of speed: $a = \dfrac{v - u}{t}$, measured in $\text{m/s}^2$.

Example 2 — Kinetic energy of a skateboarder

Standard 4 marks

Question

A skateboarder of mass $50\ \text{kg}$ is moving at $4\ \text{m/s}$. Calculate the skateboarder's kinetic energy, then explain what happens to that energy when she comes to a stop using the brakes.

Solution

Kinetic energy is the energy of motion: $E_k = \dfrac{1}{2}mv^2$.

With $m = 50\ \text{kg}$ and $v = 4\ \text{m/s}$: $E_k = \dfrac{1}{2}(50)(4)^2 = \dfrac{1}{2}(50)(16) = 400\ \text{J}$.

When she brakes, that $400\ \text{J}$ doesn't vanish — energy is conserved. Friction transforms it into heat (and a little sound).

Square the speed before multiplying — forgetting the square is the most common mistake here.

Where the marks go

  • 1 mark: Correct formula $E_k = \dfrac{1}{2}mv^2$
  • 1 mark: Correct substitution including squaring the speed ($v^2 = 16$)
  • 1 mark: Correct value $E_k = 400\ \text{J}$ with units
  • 1 mark: Explains energy is transformed to heat/sound (conservation of energy)

Key idea

Kinetic energy $E_k = \dfrac{1}{2}mv^2$ depends on the speed squared; energy is never destroyed, only transformed.