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Worked Solutions

Module 1: Cells as the Basis of Life — Worked Solutions (Preliminary Biology)

By Keshav · Intuition tutor 1 min read

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Worked examples for Preliminary Biology Module 1 — Cells as the Basis of Life. Each shows where the marks are awarded, the key idea, and a full model answer in your choice of tutor — Stella, Ella or Cassie.

How to use these

Attempt each question under exam conditions first, then check your response against the model answers. Use the tutor tabs to read the solution in the style that suits you: Stella is direct and to the point, Ella is warm and explains the why, and Cassie is concise and uses bullet points.

Example 1 — Surface area to volume ratio

Standard 4 marks

Question

Explain why cells must remain small, with reference to their surface area to volume ratio and the exchange of materials. (4 marks)

Solution

As a cell grows, its volume increases faster than its surface area, so the surface area to volume ratio falls.

The cell membrane is the surface across which materials are exchanged. The volume sets the demand — the amount of cytoplasm needing nutrients and producing waste.

If a cell gets too large, its small relative surface area cannot move materials in and out fast enough to meet the demands of its large volume. Wastes build up and nutrients run short.

Staying small keeps a high surface area to volume ratio, so exchange across the membrane is fast enough to service the whole cell. Always link the ratio to the rate of exchange — that is the mark.

Where the marks go

  • 1 mark: States that as a cell grows, volume increases faster than surface area, lowering the SA:V ratio
  • 1 mark: Identifies the surface (membrane) as the site of exchange of materials
  • 1 mark: Identifies the volume as setting the demand for materials and the production of wastes
  • 1 mark: Links a low SA:V ratio in large cells to an inadequate rate of exchange to meet the cell's needs

Key idea

Surface area governs the rate of exchange, volume governs the demand; cells stay small to keep a high SA:V ratio so exchange across the membrane keeps up with the cell's needs.

Example 2 — Active vs passive transport

Standard 5 marks

Question

Compare active transport and facilitated diffusion as mechanisms for moving substances across the cell membrane. (5 marks)

Solution

Both move substances across the membrane using membrane proteins, and both move substances that cannot cross the phospholipid bilayer easily, such as ions and glucose.

The key difference is the direction relative to the concentration gradient and the energy cost. Facilitated diffusion is passive: substances move down their concentration gradient (high to low) through a channel or carrier protein, with no ATP required.

Active transport moves substances against the concentration gradient (low to high), so it requires energy from ATP and uses carrier (pump) proteins, for example the sodium–potassium pump.

So: same use of proteins, but facilitated diffusion is passive and down the gradient, while active transport is energy-requiring and against the gradient. Make sure you give both a similarity and the differences.

Where the marks go

  • 1 mark: Identifies a valid similarity (both cross the membrane / both use transport proteins)
  • 1 mark: States facilitated diffusion is passive and requires no ATP
  • 1 mark: States active transport requires energy (ATP)
  • 1 mark: States facilitated diffusion moves substances down the concentration gradient and active transport against it
  • 1 mark: Provides a relevant example or correct protein type (e.g. carrier/pump such as the sodium–potassium pump)

Key idea

Both use membrane proteins, but facilitated diffusion is passive and moves substances down the gradient, while active transport uses ATP to move substances against the gradient.